Author Topic: maths for beginners and/or easily impressed  (Read 1298 times)

samdavo

  • Hero Member
  • *****
  • Posts: 2588
  • the trick is knowin...^ > v < - which way's up?
maths for beginners and/or easily impressed
« on: June 02, 2015, 04:53:50 AM »
...   something that arrived in an email ( 1 cent)
« Last Edit: June 02, 2015, 05:13:28 AM by samdavo »

Rob S

  • Hero Member
  • *****
  • Posts: 4546
    • Construction Estimating Program for General Contractors
Re: maths for beginners and/or easily impressed
« Reply #1 on: June 02, 2015, 07:47:02 AM »
 
Great for young people, fails after you reach 101, so as someone was saying recently on the forum here, many designcad users may not get it!!!
User since Pro-design

samdavo

  • Hero Member
  • *****
  • Posts: 2588
  • the trick is knowin...^ > v < - which way's up?
Re: maths for beginners and/or easily impressed
« Reply #2 on: June 02, 2015, 03:46:05 PM »
Lol - good one, Call it the Y1C problem (rather than the Y2K).

Gotta feeling that those two numbers multiply to 10101. 
Presumably there are some factors that multiply to 1001001 - for those forum members to which you refer :)   

PS On checking I find that the only factors of 1001001 are 3 and 333667 , both of which appear to be prime numbers. 
https://www.mathsisfun.com/numbers/prime-number-lists.htm

i.e. the senior members to whom you refer should multiply out the following :-   
3  x (your age) x 333667  (2 cents)
« Last Edit: June 02, 2015, 03:59:22 PM by samdavo »

samdavo

  • Hero Member
  • *****
  • Posts: 2588
  • the trick is knowin...^ > v < - which way's up?
Re: maths for beginners and/or easily impressed
« Reply #3 on: June 02, 2015, 04:09:56 PM »
http://www.maths.cam.ac.uk/friends/newsletters/May2007.pdf
Then there's something really simple - like proving Goldbach's Conjecture :)

Quote
As soon as one tries to combine the primes and the other
fundamental operation of arithmetic, namely addition, one
swiftly comes up with questions that have proved
impossible to answer.

Most famous amongst these is Goldbach’s Conjecture,
which hypothesises that every even number is the sum of
two primes. Given a smallish even number it is easy to
check that it is the sum of two primes, for example 104 = 31
+ 73. To a mathematician, of course, checking that every
even number less than 100,000,000 is a sum of two primes
is not good enough, and we demand a proof that
Goldbach’s Conjecture holds for all numbers.

Such a proof
is currently lacking and most experts do not expect
definitive progress on the problem in the near future.

There is a weaker version of Goldbach’s Conjecture,
which has been proven. Namely, it is known that every
sufficiently large odd number is the sum of three prime
numbers. Cambridge mathematicians G. H. Hardy and J. E.
Littlewood were the first to plot a path to a proof of this
result. It is known that “sufficiently large” in this context
can be taken to mean greater than 10^43001.

This is a number
so large that it is of mathematical, rather than merely
computational, interest to show that every odd number is
the sum of three primes.